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Question

# A boy is standing inside a train moving with a constant velocity of magnitude 10 m/s. He throws a ball vertically up with a speed of 5 m/s relative to the train. Find the radius of curvature of the path of the ball just at the time of projection. (Take g=10m/s2)

A
14 m
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B
7 m
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C
5 m
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D
10 m
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Solution

## The correct option is A 14 m Initial velocity of the ball in x-direction =10 m/s And initial velocity of the ball in y-direction =5 m/s θ=tan−1(vyvx)⇒tanθ=12⇒cosθ=2√5Since centripetal acceleration,ac=v2r(where r is the radius of curvature)∴r=v2gcosθ=52+10210×2√5 =125√520m=13.9≈14 m

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