A boy is standing on a truck which is moving with constant speed along a straight road. On a day when a wind is negligible, the boy throws a ball vertically up with some velocity. The ball comes back and falls

into boy's hand

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

behind the boy

No worries! We‘ve got your back. Try BYJU‘S free classes today!

infront of the boy

No worries! We‘ve got your back. Try BYJU‘S free classes today!

behind or infront of the boy depending on the speed of the truck and ball

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A into boy's hand

Suggest Corrections

Similar questions

Q. A boy standing on a long railroad car throws a ball straight upwards. The car is moving on the horizontal road with an acceleration of

1 m / s^{2}

and the projection speed in the vertical direction is

9.8 m / s

. How far behind the boy will the ball fall on the car?

Q. A boy standing on a long railroad car throws a ball straight upwards. The car is moving on the horizontal road with an acceleration of 1 m/s² and the projection velocity in the vertical direction is 9.8 m/s. How far behind the boy will the ball fall on the car?

A boy standing on a long raiboard car throws a ball straight upwards. The car is moving on the horizontal road with an acceleration of 1 $m / s^{2}$ and the projection velocity in the vertical direction in 9.8 m/s. How far behind the boy will the ball fail on the car ?

Q. A boy standing on a long railroad car throws a ball straight upwards. The car is moving on the horizontal road with an acceleration of

1 m s^{- 2}

and the projection velocity in the vertical direction is

9 \cdot 8 m s^{- 2}

. How far behind the boy will the ball fall on the car?

Q. A boy standing on a long railroad car throws a ball straight upwards. The car is moving on the horizontal road with an acceleration of

1 {ms}^{- 2}

and the projection velocity in the vertical direction is

9.8 m/s

. How far (in m) behind the boy will the ball fall? Take

g = 9.8 \frac{m}{s^{2}}

Join BYJU'S Learning Program