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Question

A boy is standing on the ground and flying a kite with 150 m of string at an elevation of 300. Another boy is standing on a roof of a 25 m high building and is flying his kite at an elevation 45. Both the boys are on opposite sides of both the kites. Find the length of the string (in meters), that the second boy must have so that the two kites meet.

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Solution


Let C be the position of the kite and A,B be the position of first and second boy respectively.
Let the length of the string (CD) with second boy be xmeters.
In ABC,sin30o=BCAC

12=BC100

BC=1002=50m

Now, CF=BCBF=50m10m=40m

In CFD,sin45o=CFCD

12=40x

x=402m=40×1.414=56.56 m (Take2=1.414)


Hence, the length of the string second by must-have is 56.56m.

943763_971568_ans_f67ca161a8d94abea9640e2d642e7f9d.png

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