A boy is using spectacles of focal length -50 cm. Calculate the power of the lens.

+ 0.02 D

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- 0.02 D

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+ 2D

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- 2 D

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Solution

The correct option is D - 2 D
The power of a lens is reciprocal of the focal length (in m) .
So, $P = \frac{100}{(- 50)} = - 2 D$

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A boy is using spectacles of focal length -50 cm. Calculate the power of the lens.

The correct option is D - 2 DThe power of a lens is reciprocal of the focal length (in m) . So, P=100(−50)=−2 D

The correct option is D - 2 D
The power of a lens is reciprocal of the focal length (in m) .
So, $P = \frac{100}{(- 50)} = - 2 D$