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Distance vs Displacement

A boy moves a...

Question

A boy moves along the path ABCD. What is the total distance covered by the boy?What is his net displacement?

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Solution

Total distance covered=50+40+20=110 m
ED=BC-40m
AE=AB-CD
=50-20=30m
Total displacement $= \sqrt{40^{2} + 30^{2}}$ =50 m

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