A boy of $50 k g$ is standing in a lift moving down with an acceleration $9.8 m / s^{2}$ The apparent weight of the body is-

\frac{50}{9.8} N

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50 \times 9.8 N

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50 N

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z e r o

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Solution

The correct option is D $z e r o$

$F_{p s e u d o} = M \times 9.8$
Balancing= $N = 0$
Hence, $z e r o$ .

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Similar questions

A boy of mass 40 kg is standing in a lift,
which is moving downwards with an acceleration 9.8 $m / s^{2}$ . The apparent weight of
the boy is (Take $g = 9.8 m / s^{2}$ )

Q. A boy of 50 kg is in a lift moving down with an acceleration 9.8

m s^{- 2}

. The apparent weight of the body is (g = 9.8

m s^{- 2}

)

Q. A body of mass

10 k g

is placed in a lift moving upward with an acceleration of

2 m / s^{2}

. The apparent weight of body is

(g = 9.8 m / s^{2})

Q. A force of

20 N

act on a body whose weight is

9.8 N

. What is the mass of the body and how much is its acceleration.

(g = 9.8 m / s^{2})

Q. A person of mass

50 k g

is standing in lift. What weight will he experience if the lift is moving upwards with acceleration

2 m / s^{2}

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A boy of 50kg is standing in a lift moving down with an acceleration 9.8m/s2 The apparent weight of the body is-

The correct option is D zeroFpseudo=M×9.8Balancing=N=0Hence, zero.

A boy of $50 k g$ is standing in a lift moving down with an acceleration $9.8 m / s^{2}$ The apparent weight of the body is-

The correct option is D $z e r o$

$F_{p s e u d o} = M \times 9.8$
Balancing= $N = 0$
Hence, $z e r o$ .