A boy of height 1m stands in front of a convex mirror. His distance from the mirror is equal its focal length. The height of his image is
0.5m
using mirror formula: 1v+1−f=1fV=f2
where 'v' is the image distance, 'u' is the object distance and 'f' is the focal length of the mirror
1v+1−f=1fV=f2
We write magnification as vih0=−vu wherehi is the height of image and ho is the height of object. Placing the value of v, we can get hi=12