A boy of mass 30 kg is sitting at a distance of 2 m from the middle of a seesaw. Where should a boy of mass 40 kg sit so as to balance the see-saw?

3 m

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2 m

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2.5 m

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1.5 m

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Solution

The correct option is D
1.5 m

Mass₁ = 30 kg (m₁)

Mass₂ = 40 kg (m₂)

Distance of mass₁ from centre = 2 m ……………(r₁)

Let distance of mass₂ from centre = r₂.

We know for balanced condition, by Principle of Moments:

m₁r₁ = m₂r₂

60 = 40 r₂

r₂ = 1.5 m

This means mass m₂ should be placed at 1.5 m away from the centre in opposite direction to that of mass₁.

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