A boy of mass 30 kg sitting at a distance of 2m from the middle of see-saw. Where should a boy of mass 40 kg sit so as to balance the see -saw?

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Solution

Let the distance of 40 kg. from the mean position be 'x' m.
Using principle of moments,
$30 \times 2 = 40 \times x$
$x = 1.5 m .$
A boy of mass 40 kg should sit at $1.5 m$ from the middle of see-saw.

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A boy of mass 30 kg sitting at a distance of 2m from the middle of see-saw. Where should a boy of mass 40 kg sit so as to balance the see -saw?

Let the distance of 40 kg. from the mean position be 'x' m.Using principle of moments,30×2=40×xx=1.5m.A boy of mass 40 kg should sit at 1.5m from the middle of see-saw.

Let the distance of 40 kg. from the mean position be 'x' m.
Using principle of moments,
$30 \times 2 = 40 \times x$
$x = 1.5 m .$
A boy of mass 40 kg should sit at $1.5 m$ from the middle of see-saw.