The correct option is A 1:1
While climbing, both the boy and the girl have to do work against gravity.
Given, mass of the boy, m1=40 kg, mass of the girl,m2=30 kg, number of steps=30, height of each step =20 cm, time taken by boy, t1=2 min, time taken by girl, t2=1.5 min and acceleration due to gravity, g=10 ms−2.
Force of gravity on boy, F1=m1g=40×10=400 N
Force of gravity on girl, F2=m2g=30×10=300 N
Total height climbed,h=number of steps×height of each step⇒30×20=600 cm=6 m (This height is same for the boy and the girl)
Work done by the boy, W1=F1×h=400×6=2400 J
Work done by the girl, W2=F2×h=300×6=1800 J
∴ W1:W2=2400:1800=4:3.
Power developed by girlPower developed by boy=W1t1W2t2=W1W2×t2t1⇒43×1.52=1:1
Therefore, the power developed is the same for the boy and girl.