A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and $g = 10 m s^{- 2}$ , the horizontal force that he is applying on the pole is

300 N

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400 N

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500 N

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600 N

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Solution

The correct option is C
500 N

As the boy is climbing the pole at a constant speed (no acceleration), the force of friction must be just balanced by his weight, i.e.,
$μ R = m g \Rightarrow R = \frac{m g}{μ} = \frac{40 \times 10}{0.8} = 500 N$ .
Hence, the correct choice is (c).

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A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g=10 ms−2, the horizontal force that he is applying on the pole is

The correct option is C 500 N As the boy is climbing the pole at a constant speed (no acceleration), the force of friction must be just balanced by his weight, i.e., μR=mg⇒R=mgμ=40×100.8=500 N. Hence, the correct choice is (c).

A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and $g = 10 m s^{- 2}$ , the horizontal force that he is applying on the pole is

The correct option is C
500 N

As the boy is climbing the pole at a constant speed (no acceleration), the force of friction must be just balanced by his weight, i.e.,
$μ R = m g \Rightarrow R = \frac{m g}{μ} = \frac{40 \times 10}{0.8} = 500 N$ .
Hence, the correct choice is (c).