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Question

A boy of mass 40 kg running at 5 m/s jumps on a trolley of 20 kg moving in the same direction at 2 m/s. Find their common velocity.

A
0 m/s
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B
4 m/s
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C
7 m/s
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D
10 m/s
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Solution

The correct option is B 4 m/s
The momentum of the system, consisting of the boy and the trolley, must be conserved in the absence of the net external force.

Initial momentum of the system,
pi = m1u1 + m2u2
pi = 40 x 5 + 20 x 2 = 240 kg m/s

Finally, both the boy and the trolley are moving together with the same velocity.
Hence, the final momentum of the system, pf = (40 + 20) x v = 60v

By the conservation of momentum,
pi = pf
⇒ 240 = 60v
⇒ v = 24060
v = 4 m/s

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