A boy of mass m is standing on a block of mass M kept on a rough surface. When the boy walks from left to right on the block, the centre of mass(boy + block) of the system.
A
Remains stationary
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B
Shifts towards left
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C
Shifts towards right
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D
Shifts toward right if M > m and toward left if M < m.
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Solution
The correct option is C Shifts towards right Center of mass shift towards right as man moves towards left to right so block will move from right to left and hence external force of friction act opposite to it that is towards right.