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Standard XII

Physics

Throwing and Catching at Same Height

A boy project...

Question

A boy projects a stone vertically perpendicular to the trolley car with a speed $v$ . If the trolley car moves with a constant velocity $u$ , the time of flight of the stone is:

\frac{2 v}{g}

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\frac{u + v^{2}}{g}

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none of these

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\frac{2 u}{g}

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Solution

The correct option is C none of these
Resolve the velocity 𝑣 into horizontal and vertical component.

$v_{0} sin θ = v$
$v_{0} cos θ = u$

Time of flight depends on vertical component of velocity.

$T = \frac{2 v_{0} sin θ}{g} = \frac{2 v}{g}$

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Throwing and Catching at Same Height

Standard XII Physics

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A boy projects a stone vertically perpendicular to the trolley car with a speed v. If the trolley car moves with a constant velocity u, the time of flight of the stone is:

The correct option is C none of theseResolve the velocity 𝑣 into horizontal and vertical component. v0sinθ=v v0cosθ=u Time of flight depends on vertical component of velocity. T=2v0sinθg=2vg

A boy projects a stone vertically perpendicular to the trolley car with a speed $v$ . If the trolley car moves with a constant velocity $u$ , the time of flight of the stone is:

The correct option is C none of these
Resolve the velocity 𝑣 into horizontal and vertical component.

$v_{0} sin θ = v$
$v_{0} cos θ = u$

Time of flight depends on vertical component of velocity.

$T = \frac{2 v_{0} sin θ}{g} = \frac{2 v}{g}$