Question

A boy pulls a toy having two carriages placed on a frictionless table by applying a force of $1.5$ newton at ${30}^o$ in a vertical plane. Calculate (i) the acceleration of the $40g$ carriage, (ii) the acceleration of the $20g$ carriage and (iii) the tension in the string fastened between the two carriages.

Answer 1

As per the information, since both the toys are fastened by string so the acceleration of both the toys will be same and equal to the accleration of the system.

$\therefore a_{system}=a_{40g}=a_{20g}=\frac{40g+20g}{1.5cos{60}^o}=80g$

Now for the 2nd carriage$T=20\times 80g=1600g$

the tension in the string fastened between the two carriages is = 1600g N.