A boy ran from his house to school at a speed of 10 km/h while returning his Speed was 20 km/h what is the average speed of the boy for round trip

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Solution

Dear Student
$A v e r a g e S p e e d = \frac{T o t a l D i s \tan c e}{T o t a l t i m e} L e t d i s \tan c e b e t w e e n h o u s e a n d s c h o o l i s d W h e n g o i n g f r o m h o u s e t o s c h o o l t i m e t a k e n i s t_{1} = \frac{d}{10} W h e n g o i n g f r o m s c h o l l t o h o u s e t i m e t a k e n i s t_{2} = \frac{d}{20} A v e r a g e S p e e d = \frac{2 d}{t_{1} + t_{2}} = \frac{2 d}{\frac{d}{10} + \frac{d}{20}} A v e r a g e S p e e d = \frac{2 d}{\frac{2 d + d}{20}} = \frac{2 d}{\frac{3 d}{20}} = \frac{2}{3} \times 20 = 13.33 K m / h$
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A boy ran from his house to school at a speed of 10 km/h while returning his Speed was 20 km/h what is the average speed of the boy for round trip

Dear Student Average Speed =Total DistanceTotal timeLet distance between house and school is dWhen going from house to school time taken is t1 =d10When going from scholl to house time taken is t2 =d20Average Speed =2d t1+ t2 =2dd10+d20Average Speed =2d2d+d20 =2d3d20 =23×20=13.33 Km/h Regards