Question

A boy scored the following marks in various tests during a term, each test being marked out of $20$.

$15,17,16,7,10,12,14,16,19,12,16$. The median marks are

• A. 16
• B. 15
• C. 18
• D. 13

Answer 1

Answer: (B)

Scores done by the boy out of $20$ are,

$15,17,16,7,10,12,14,16,19,12,16$

To find the median of the data, we have to arrange it into either ascending order or descending order.

$\Rightarrow 7,10,12,12,14,15,16,16,16,17,19$

Here, the number of observations are $=11$ (odd)

If $n$ is odd the $(\frac{n+1}{2}{)}^{\text{th}}$ observation

$\Rightarrow$ Median $=(\frac{11+1}{2}{)}^{\text{th}}$ observation

$=6\text{th}$ observation

Now, in $7,10,12,12,14,15,16,16,16,17,19$

$6\text{th}$ observation is $15$.

Therefore, The median of the marks is $15$.

Hence, Option $A$ is correct.