Question

A boy standing at a point O finds his kite flying at a point P with distance OP = 25 m. It is at a height of 5 m from the ground. When the thread is extended by 10 m from P, it reaches a point Q. What will be the height QN of the kite from the ground?

• A. 5 m
• B. 6 m
• C. 7 m
• D. 8 m

Answer 1

The correct option is C 7 m

Let the angle O be $“\theta ”$

In $\Delta ONQ$
sinθ = opposite side/hypotenuse
$=\frac{QN}{OQ}$
$=\frac{h}{(25+10)}$
$=\frac{h}{35}$

In $\Delta OMP$
$\sin \theta =\frac{PM}{OP}=\frac{5}{25}=\frac{1}{5}$

So,
$\frac{h}{35}=\frac{1}{5}$

Hence, $h=7$
So, the height QN of the kite from the ground is 7 m.