A boy standing at a point $O$ finds his kite flying at a point $P$ with distance $O P = 25$ m. It is at a height $5$ m from the ground. When thread is extended by $10$ m from $P$ , it reaches a point $Q$ . What will be the height $Q N$ of the kite from the ground? (use trigonometric ratios)

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Solution

REF.Image
$∠ P O M = ∠ Q O N, = θ$
$s i n θ = \frac{5}{25} = \frac{h}{25 + 10}$
$\frac{5}{25} = \frac{h}{35} \Rightarrow h = 7 m$

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A boy standing at a point O finds his kite flying at a point P with distance OP=25 m. It is at a height 5 m from the ground. When thread is extended by 10 m from P, it reaches a point Q. What will be the height QN of the kite from the ground? (use trigonometric ratios)

REF.Image∠POM=∠QON,=θsinθ=525=h25+10525=h35⇒h=7m

A boy standing at a point $O$ finds his kite flying at a point $P$ with distance $O P = 25$ m. It is at a height $5$ m from the ground. When thread is extended by $10$ m from $P$ , it reaches a point $Q$ . What will be the height $Q N$ of the kite from the ground? (use trigonometric ratios)

REF.Image
$∠ P O M = ∠ Q O N, = θ$
$s i n θ = \frac{5}{25} = \frac{h}{25 + 10}$
$\frac{5}{25} = \frac{h}{35} \Rightarrow h = 7 m$