wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A boy standing between two cliffs claps and hears 2 echoes after 2s and 2.5 s respectively. If the velocity of sound is 330 ms1, find the distance between he two cliffs :

A
742.50 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
274.50 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
472.50 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
442.50 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 742.50 m
Let d1 and d2 be the distances of cliffs from the boy .
for first echo , which is heard after 2s ,
total distance travelled by sound =2d1 ,
given v=330m/s ,
we have , distance=speed×time ,
2d1=330×2 ,
or d1=660/2=330m ,
for second echo , which is heard after 2.5s ,
total distance travelled by sound =2d2 ,
given v=330m/s ,
we have , distance=speed×time ,
2d2=330×2.5 ,
or d2=825/2=412.5m ,
therefore , distance between cliffs , d=d1+d2=330+412.5=742.5m

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Echo tackle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon