A boy standing between two cliffs claps and hears 2 echoes after 2s and 2.5 s respectively. If the velocity of sound is 330 ms−1, find the distance between he two cliffs :
A
742.50 m
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B
274.50 m
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C
472.50 m
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D
442.50 m
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Solution
The correct option is A742.50 m Let d1 and d2 be the distances of cliffs from the boy .
for first echo , which is heard after 2s ,
total distance travelled by sound =2d1 ,
given v=330m/s ,
we have , distance=speed×time ,
2d1=330×2 ,
or d1=660/2=330m ,
for second echo , which is heard after 2.5s ,
total distance travelled by sound =2d2 ,
given v=330m/s ,
we have , distance=speed×time ,
2d2=330×2.5 ,
or d2=825/2=412.5m ,
therefore , distance between cliffs , d=d1+d2=330+412.5=742.5m