A boy standing on the surface of the Moon throws a ball of mass 2 kg vertically upwards with an initial speed of 20 m/s. What is the maximum height attained by the ball? (Given: Weight of the object on the Moon = ⅙ weight of the object on Earth; Acceleration due to gravity on Earth = 10 m/s $^{2}$ )

30 m

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120 m

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240 m

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60 m

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Solution

The correct option is B 120 m
Acceleration due to gravity of the Moon is ⅙ times that of the Earth. Thus, the maximum height can be calculated using the third equation of motion.

$v^{2} - u^{2} = 2 a s (0)^{2} - (20)^{2} = 2 (\frac{- 10}{6}) s s = 120 m$

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A boy standing on the surface of the Moon throws a ball of mass 2 kg vertically upwards with an initial speed of 20 m/s. What is the maximum height attained by the ball? (Given: Weight of the object on the Moon = ⅙ weight of the object on Earth; Acceleration due to gravity on Earth = 10 m/s2)

The correct option is B 120 mAcceleration due to gravity of the Moon is ⅙ times that of the Earth. Thus, the maximum height can be calculated using the third equation of motion. v2−u2=2as(0)2−(20)2=2(−106)ss=120m

The correct option is B 120 m
Acceleration due to gravity of the Moon is ⅙ times that of the Earth. Thus, the maximum height can be calculated using the third equation of motion.

$v^{2} - u^{2} = 2 a s (0)^{2} - (20)^{2} = 2 (\frac{- 10}{6}) s s = 120 m$