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Relative Acceleration

A boy stands ...

Question

A boy stands at a distance 'd' behind the bus. The bus and boy start moving simultaneously; the boy with an initial and constant velocity of 'v' and the bus starts from rest with an acceleration of 'a' What is the minimum value of 'v' such that the boy successfully catches the bus?

A

\sqrt{2 a d}

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B

\sqrt{a d}

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C

\sqrt{a d / 2}

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D

infinite

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Solution

The correct option is A $\sqrt{2 a d}$
Hey try to solve this on your own, take 5 minutes and think. Then go on to the next set of videos to learn multiple approaches to it.

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Q. Hey, try to solve this question using relative motion concepts now; by moving to the frame of the bus.
A boy stands at a distance 'd' behind the bus. The bus and boy start moving simultaneously; the boy with an initial and constant velocity of 'v' and the bus starts from rest with an acceleration of 'a' What is the minimum value of 'v' such that the boy successfully catches the bus?

Q. A bus starts from rest and moves with a uniform acceleration of

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