wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A boy starting from rest is accelerated uniformly for 30 s. If x1,x2,x3 are the distance travelled in first 10 s, next 10 s and last 10 s respectively, then x1:x2:x3 is

A
1:2:3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1:1:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1:3:5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1:3:9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1:3:5
The distance travelled in first 10 seconds can be calculated from the second equation of motion
x1=ut+12at2
x1=0+12a(10)2=50a
Similarly, the distance travelled in 20 seconds will be
x1+x2=ut+12a(20)2
x1+x2=200a
x2=150a
and distance travelled in 30 seconds
x1+x2+x3=0+12a(30)2
x1+x2+x3=450a
x3=(450200)a=250a
Therefore, the ratio
x1:x2:x3=1:3:5
Therefore, option C is correct.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equations of Motion tackle new
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon