A boy travels a distance between two points at a speed of 25km/hr and return back at a speed of 30 km/hr find average speed and average velocity

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Solution

Dear Student,
$A v e r a g e v e l o c i t y = \frac{n e t d i s p l a c e m e n t}{t i m e} = \frac{0}{t} = 0 h e r e n e t d i s p l a c e m e n t i s z e r o a s b o y r e t u r n s b a c k t o s a m e p o i n t . A v e r a g e v e l o c i t y = \frac{t o t a l d i s \tan c e}{t i m e} = \frac{2 d}{\frac{d}{25} + \frac{d}{30}} = \frac{2 \times 25 \times 30}{25 + 30} = 27.25 k m / h$
Regards

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A boy travels a distance between two points at a speed of 25km/hr and return back at a speed of 30 km/hr find average speed and average velocity

Dear Student, Average velocity=net displacement time =0t=0here net displacement is zero as boy returns back to same point.Average velocity=total distancetime =2dd25+d30=2×25×3025+30=27.25km/h Regards