Question

A boy walks a distance $30m$ in $1$ minute and another $30m$ in $1.5$ minute. Describe the type of motion of the boy and find his average speed in $m{s}^{-1}$.​

Answer 1

The boy walks a distance $30m$ in $1$ minute and another $30m$ in $1.5$ minute, it means the boy covers unequal distances in equal time intervals. Thus, the motion is non-uniform.​
Given, Total distance travelled $=(30+30)m$​
$=60m$ ​
Time taken taken $=(1+1.5)min$ ​
$=2.5min=150sec$
To find, Average speed​:

$\text{Average speed}=\frac{\text{Total distance covered}}{\text{Time taken}}$

$=\frac{60m}{150sec}=0.4m{s}^{-1}$
So, the average speed of car is $0.4m{s}^{-1}$.​