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Question

A boy was carrying out an experiment on the solubility of a gas in the water.He took a solute gas A and dissolved it in a liquid solvent(Water) B at a particular temperature T and pressure P.At that point he got some solubility value S. Later, he observed the value of solubility by

i)increasing temperature of water from T to T' and

ii)decreasing pressure on water surface from P to P'.

He got the new solubility S'.Then what is the relationship between former solubility S and latter solubility S'?


A

S' > S

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B

S' < S

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C

S' = S

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D

S' = 2S

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Solution

The correct option is B

S' < S


Effect of temperature on the solubility of gases in water-

On increasing temperature of the water, the solubility of gases in water decreases because the kinetic energy of liquid increases and dissolved gases will escape out of the liquid and solubility decreases. On the other hand, lowering the temperature of the water will lower down the kinetic energy of water and more gases will dissolve and solubility increases.

Effect of pressure on the solubility of gases in water-

On increasing pressure on the water surface, more amount of gas dissolves in water because of the compressible property of gases and vice-versa.

So from above explanation, we can say that former solubility is more than latter solubility i.e, S > S'


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