A boy was offered a bonus if he sold 100 subscriptions to a magazine. Each day he sold 3 subscriptions more than he had on the previous day and on the eighth day he reached his 100 quota. how many subscription did he sell each day?

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Solution

Dear Student,
Arithmetic Sequence with common difference = 3
and S(8) = 100
----
Solve:
S(8) = (8/2)(1st + last)
100 = 4(1st + last)
1st + last = 25
----
a(n) = 1st+(n-1)d
last = a(8) = 1st+73
---
Solve:

1st+ [1st+21] = 25
21st + 21 = 25
1st = 2
----
1st day: 2
2nd: 5
3rd: 8
4th: 11
5th: 14
6th: 17
7th: 20
8th: 23
---
Sum = 100
Regards

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