Question

$\left(A\right)Br{F}_3+Sb{F}_5\to \left[Br{F}_2{]}^{+}\right[Sb{F}_6{]}^{-}$

$or$

$\left(B\right)Br{F}_5+Sb{F}_5\to \left[Br{F}_4{]}^{+}\right[Sb{F}_5{]}^{-}$

Mark your answer as A if reaction ( A ) is correct or B if reaction ( B ) is correct.

Answer 1

${BrF}_3+{SbF}_5⟶{\left[{BrF}_2\right]}^{+}{\left[Sb{F}_6\right]}^{-}$

Bromine (III) Fluoride reacts with Antimony Fluoride as a fluoride donar. It donates fluorine, acquiring a net positive charge and giving net negative charge to Antimony Fluoride.

Option:- $A$