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Thermal Expansion

A brass rod a...

Question

A brass rod and a lead rod each 80 cm long at $0^{\circ} C$ ,are clamped together at one end with their free ends coinciding. The separation of the free ends of the rods, if the system is placed in steam bath is

0.2 mm

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0.8 mm

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1.4 mm

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1.6 mm

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Solution

The correct option is B 0.8 mm
In this case dt = 100
$l_{o p b} = l_{o b r}$ = 80 cm
$l_{2 p b} - l_{2 b r}$ = 80 X 10 X 100 X $10^{- 6}$
= 0.08 cm = 0.8 mm

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0^{\circ} C

0^{\circ} C

(α_{b r a s s} = 18 \times 10^{- 6} /^{\circ} C a n d α_{l e a d} = 28 \times 10^{- 6} /^{\circ} C)

0^{\circ} C

(α_{b r a s s} = 18 \times 10^{- 6} /^{\circ} C a n d α_{l e a d} = 28 \times 10^{- 6} /^{\circ} C)

80 cm

0^{\circ} C

[α_{brass} = 18 \times 10^{- 6} /^{\circ} C

α_{lead} = 28 \times 10^{- 6} /^{\circ} C and temperature of steam = 100^{\circ} C]

80 cm

0^{\circ} C

[α_{brass} = 18 \times 10^{- 6} /^{\circ} C

α_{lead} = 28 \times 10^{- 6} /^{\circ} C and temperature of steam = 100^{\circ} C]

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