You visited us 1 times! Enjoying our articles? Unlock Full Access!

Young's Modulus of Elasticity

A brass rod a...

Question

A brass rod and lead rod each 80 cm long at $0^{\circ} C$ are clamped together at one end with their free ends coinciding. The separation of free ends of the rods if the system is placed in a steam bath is

0.2 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.8 mm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.4 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.6 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 0.8 mm
Increase in length of the brass rod= $l_{0} α_{b r a s s} Δ θ$
Increase in length of lead rod= $l_{0} α_{l e a d} Δ θ$
Thus separation of free ends of rods on expansion= $l_{0} (α_{l e a d} - α_{b r a s s}) Δ θ$
$Δ θ = 100^{\circ} C$
$⟹$ Separation= $0.8 m m$

Suggest Corrections

Similar questions

0^{\circ} C

0^{\circ} C

(α_{b r a s s} = 18 \times 10^{- 6} /^{\circ} C a n d α_{l e a d} = 28 \times 10^{- 6} /^{\circ} C)

0^{\circ} C

(α_{b r a s s} = 18 \times 10^{- 6} /^{\circ} C a n d α_{l e a d} = 28 \times 10^{- 6} /^{\circ} C)

80 cm

0^{\circ} C

[α_{brass} = 18 \times 10^{- 6} /^{\circ} C

α_{lead} = 28 \times 10^{- 6} /^{\circ} C and temperature of steam = 100^{\circ} C]

80 cm

0^{\circ} C

[α_{brass} = 18 \times 10^{- 6} /^{\circ} C

α_{lead} = 28 \times 10^{- 6} /^{\circ} C and temperature of steam = 100^{\circ} C]

Join BYJU'S Learning Program