Question

A brass sphere of mass $0.2kg$ falls freely from a height of $24m$ and bounces to a height of $8m$ from the ground. If the dissipated energy in this process is desorbed by the sphere the rose in its temperature is (specific heat of brass = $360Jk{g}^{-1}{k}^{-1}$ and $g=10m{s}^{-2}$ ).

• A. ${0.44}^{\circ }$
• B. ${0.66}^{\circ }$
• C. ${0.77}^{\circ }$
• D. ${0.88}^{\circ }$

Answer 1

The correct option is A ${0.44}^{\circ }$

$\begin{array}{c}mg\left(24-8\right)=ms\Delta T\\ \Rightarrow 10\times 16=360\left(\Delta T\right)\\ \Delta T=\frac{160}{360}={0.44}^{0}C\\ Hence,\\ option\left(A\right)iscorrectanswer\end{array}$