a breaking stress of metal is 7.810power9 Newton per metresquare.calculate the maximum length of wire made of this metal if density of metal is 7.810power3 kilogram per metrecube.

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Solution

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$S t r e s s = \frac{f o r c e}{a r e a} o r \frac{w e i g h t}{a r e a (A)} o r \frac{m a s s \times a c c . d u e g r a v i t y}{a r e a (A)} o r \frac{d e n s i t y \times v o l u m e \times g}{A r e a} o r, \frac{d e n s i t y \times a r e a \times l e n g t h \times g}{a r e a} o r, S t r e s s_{m a x} = d e n s i t y \times l e n g t h_{m a x} \times a c c . d u e t o g r a v i t y o r, l_{m a x} = \frac{S t r e s s_{m a x}}{d e n s i t y \times g} o r \frac{7.8 \times 10^{9} K g / m s^{2}}{7.8 \times 10^{3} k g / m^{3} \times 9.8 m / s^{2}} o r 1.02 \times 10^{5} m$

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Similar questions

7.8 \times 10^{9} N M^{- 2}

= 7.8 \times 10^{3} k g m^{- 3}

g = 10 N k g^{- 1}

^{3}

4.9 c m

7.8 g p e r c m^{3}

π = 22 / 7

7800 k g / m^{3}

^{3}

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