Question

A brick having weight 30 N is 21 cm long, 10 cm wide and 6 cm high. The face of the brick on the ground having dimensions 21 cm and 6 cm is in contact with the ground. Find the pressure exerted on the ground by the face of brick.

Answer 1

Step 1: Given data

Force, $F=30N$

Length, $L=21Cm$

Breadth, $B=6Cm$

Step 2: Formula used

The formula for area and pressure is given as,

$Area\left(A\right)=L\times B$

$Pressure\left(P\right)=\frac{F}{A}$

Step 3: Finding the area

On putting all the values we have,

$$\begin{gathered} Area\left(A\right)=L\times B=21cmx6cm \\ A=126cm²=126\times {10}^{-4}m² \end{gathered}$$

Step 4: Finding Pressure

On putting all the values we have,

$$\begin{gathered} P=\frac{F}{A} \\ =\frac{30}{126\times {10}^{-4}}=2381\frac{N}{m^2} \\ =2381Pa. \end{gathered}$$

Hence, the pressure exerted by the body is 2381 Pa.