Question

A brick whose length, breadth and height are $5$ mm, $20$ mm and $15$ mm respectively has total surface area=

• A. $940m{m}^2$
• B. $950m{m}^2$
• C. $910m{m}^2$
• D. $930m{m}^2$

Answer 1

Answer: (B)

$950m{m}^2$

Surface area of the cuboid $=2(lb+bh+hl)$
$=2\times (5\times 20+20\times 15+15\times 5)$
$=2\times (100+300+75)$
$=2\times \left(475\right)$
$=950m{m}^2$