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Question

A bright object 50 mm high stands on the axis of a concave mirror of focal length 100 mm and at a distance of 300 mm from the concave mirror. How big will the image be?

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Solution

Distance of the object from the mirror 'u' = -300 mm
Height of the object 'ho' = 50 mm
Focal length of the mirror 'f' = -100 mm
We have to find the distance of the image 'v' and the height of the image 'hi'.
1f=1v+1u1-100=1v+1-300-1100=1v-1300 1v=1300-11001v=1300-11001v=-2300v=-150 mmThus, the image will be at a distance of 150 mm in front of the mirror.Now, using the magnification formula, we getm=hiho=-vuhi50=-(-150)-300=-12hi =-502=-25 mmThus, the size of the image will be 25 mm.

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