Question

A broadcast radio transmitter radiates $12kW$ when percentage of modulation is $50\%$, then the unmodulated carrier power is

• A. $5.67kW$
• B. $7.15kW$
• C. $10.67kW$
• D. $12kW$

Answer 1

Answer: (C)

$10.67kW$

Percentage of modulation is $50$% i.e. $m=0.5$
Transmitted power $P_t=12kW$
Thus unmodulated carrier wave $P_c=\frac{P_t}{1+\frac{m^2}{2}}$
$\therefore$ $P_c=\frac{12}{1+\frac{{0.5}^2}{2}}=10.67kW$