Question

A brown eyed couple has a blue-eyed child. The trait of brown eye (B) is dominant over blue-eye (b). What is the genotype of the couple?

• A. Bb $\times$ Bb
• B. BB$\times$ BB
• C. BB $\times$ Bb
• D. BB $\times$ bb.

Answer 1

Answer: (A)

Bb $\times$ Bb

Since both parents are brown eyed and the child is blue eyed (bb) therefore both the parents can not be pure dominant or pure recessive so the genotype of parents must be Bb×Bb.

Hence, the correct option is 'Bb × Bb'