Question

A bucket containing water is tied to one end of a rope of length $1.8m$. It is rotated about the other end so that water does not spill out. What is the minimum velocity of the bucket at which this can happen? (in $m/s$)

• A. $4.2$
• B. $2.3$
  
• C. $6.3$
  
• D. $4.9$
  

Answer 1

The correct option is A $4.2$

the minimum velocity of the bucket so that water does not spill out is given by

$v=\sqrt{\left(rg\right)}=\sqrt{(1.8\ast 10)}=\sqrt{\left(18\right)}=4.2m/s$

where r is length of rope and g is acceleration due to gravity