A bucket containing water is whirled in a vertical circle at arm's length. Find the minimum speed at the top to ensure that no water spills out. Also, find corresponding angular speed. (Assume $r = 0.75 m$ )

Open in App

Solution

Centrifugal force should balance the weight
$\Rightarrow \frac{m v^{2}}{r} = m r \Rightarrow v = \sqrt{r g} = \sqrt{0.75 \times 10} = 2.74 m s$
$w = \frac{v}{r} = 3.65 r a d / s$

Suggest Corrections

Similar questions

Q. A bucket containing water is whirred in a vertical circle at arm's length. find the minimum speed at the top to ensure that no- water spills out then

(given=r=0.75m)(given=r=0.75m)

Q. A bucket tied at the end of a

1.6 m

long string is whirled in a vertical circle with a constant speed. What should be the minimum speed, so that the water from the bucket does not spill out when the bucket is at the highest position during the rotation?

(g = 10 m / s^{2})

Q. A bucket tied at the end of a

1.6 m

long string is whirled in a vertical circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill, when the bucket is at the highest position (Take

g = 10 m / {s e c}^{2})

Q. The minimum speed of a bucket full of water whirled in a vertical circle of radius

10 m

at the highest point so that the water may not fall

(g = 10 {m s}^{- 2})

A cylindrical bucket filled with water is whirled around in a vertical circle of radius r. What can be the minimum speedat the top of the path if water does not fall out from the bucket? If it continues with this speed, what normal contact force the bucket exerts on water at the lowest point of the path?

Join BYJU'S Learning Program

A bucket containing water is whirled in a vertical circle at arm's length. Find the minimum speed at the top to ensure that no water spills out. Also, find corresponding angular speed. (Assume r=0.75m )

Centrifugal force should balance the weight⇒mv2r=mr⇒v=√rg=√0.75×10=2.74msw=vr=3.65 rad/s

A bucket containing water is whirled in a vertical circle at arm's length. Find the minimum speed at the top to ensure that no water spills out. Also, find corresponding angular speed. (Assume $r = 0.75 m$ )

Centrifugal force should balance the weight
$\Rightarrow \frac{m v^{2}}{r} = m r \Rightarrow v = \sqrt{r g} = \sqrt{0.75 \times 10} = 2.74 m s$
$w = \frac{v}{r} = 3.65 r a d / s$