Question

A bucket contains 10 brown balls, 8 green balls, and 12 red balls. A ball is drawn. What is the probability that the ball will be brown?

• A. 4/15
• B. 1/3
• C. 2/5
• D. 3/5

Answer 1

The correct option is B

1/3

Given,

Number of brown balls = 10

Number of green balls = 8

Number of red balls = 12

Total number of balls = Total number of outcomes = 10 + 8 + 12 = 30

Number of favourable outcomes = 10

Probability of an event, P(E) $=\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$

P (drawn ball is brown) = $\frac{10}{30}=\frac{1}{3}$

Therefore, the probability that the ball will be brown is $\frac{1}{3}$.