A bucket contains 10 brown balls, 8 green balls, and 12 red balls and you pick one randomly without looking. What is the probability that the ball will be brown?

$\frac{4}{15}$

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$\frac{1}{3}$

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0.61

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0.33

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Solution

The correct options are
B
$\frac{1}{3}$

D
0.33

There are a total of 10 + 8 + 12 = 30 balls, out of which 10 are brown.
The required probability is $\frac{10}{30}$ = $\frac{1}{3}$ .

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A bucket contains 10 brown balls, 8 green balls, and 12 red balls and you pick one randomly without looking. What is the probability that the ball will be brown?

The correct options are B 13 D 0.33 There are a total of 10 + 8 + 12 = 30 balls, out of which 10 are brown. The required probability is 1030 = 13.

The correct options are
B
$\frac{1}{3}$

D
0.33

There are a total of 10 + 8 + 12 = 30 balls, out of which 10 are brown.
The required probability is $\frac{10}{30}$ = $\frac{1}{3}$ .