A bucket contains 8 kg of water at 25-C and 2 kg of water at 80-C is poured into it- Neglecting the heat absorbed by the bucket- calculate the final temperature of water-

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Byju's Answer

Standard X

Physics

Method of Mixtures

A bucket cont...

Question

A bucket contains $8 kg$ of water at $25^{\circ} C$ and $2 kg$ of water at $80^{\circ} C$ is poured into it. Neglecting the heat absorbed by the bucket, calculate the final temperature of water.

36^{\circ} C

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40^{\circ} C

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38^{\circ} C

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56^{\circ} C

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Solution

The correct option is A $36^{\circ} C$
Let $s$ be the specific heat capacity of water and the final temperature be $T$ .

Heat lost by hot water $=$ Heat gained by cold water
$\Rightarrow 2 \times s \times (80^{\circ} C - T) = 8 \times s \times (T - 25^{\circ} C)$
$\Rightarrow 160^{\circ} C - 2 T = 8 T - 200^{\circ} C$
$\Rightarrow T = 36^{\circ} C$

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A bucket contains 8 kg of water at 25∘C and 2 kg of water at 80∘C is poured into it. Neglecting the heat absorbed by the bucket, calculate the final temperature of water.

The correct option is A 36∘CLet s be the specific heat capacity of water and the final temperature be T. Heat lost by hot water = Heat gained by cold water ⇒2×s×(80∘C−T)=8×s×(T−25∘C) ⇒160∘C−2T=8T−200∘C ⇒T=36∘C

A bucket contains $8 kg$ of water at $25^{\circ} C$ and $2 kg$ of water at $80^{\circ} C$ is poured into it. Neglecting the heat absorbed by the bucket, calculate the final temperature of water.