A bucket contains 8 kg of water at 25-C and 2 kg of water at 80-C is poured into it- Neglecting the heat absorbed by the bucket- calculate the final temperature of water-

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Method of Mixtures

A bucket cont...

Question

A bucket contains $8 kg$ of water at $25^{\circ} C$ and $2 kg$ of water at $80^{\circ} C$ is poured into it. Neglecting the heat absorbed by the bucket, calculate the final temperature of water.

36^{\circ} C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

40^{\circ} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

38^{\circ} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

56^{\circ} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $36^{\circ} C$
Let $s$ be the specific heat capacity of water and the final temperature be $T$ .

Heat lost by hot water $=$ Heat gained by cold water
$\Rightarrow 2 \times s \times (80^{\circ} C - T) = 8 \times s \times (T - 25^{\circ} C)$
$\Rightarrow 160^{\circ} C - 2 T = 8 T - 200^{\circ} C$
$\Rightarrow T = 36^{\circ} C$

Suggest Corrections

Similar questions

200 g

of hot water at

80^{o} C

is added to

300 g

of cold water at

10^{o} C

. Neglecting the heat taken by the container, calculate the final temperature of the mixture of water. Specific heat capacity of water

= 4200 J k g^{- 1} K^{- 1}

200 g

of hot water at

80^{\circ} C

is added to

300 g

of cold water at

10^{\circ} C

. Neglecting the heat taken by the container, calculate the final temperature of the mixture of water. Specific heat capacity of water =

44200 J k g^{- 1} K^{- 1}

2

kg water at

100^{\circ} C

and

2.5

kg water at

50^{\circ} C

is kept in two identical containers

A

and

B

respectively of water equivalent

0.5

kg. If water of container

A

is placed poured into container

B

the final temperature of mixture is

T_{1}

and if water of container

B

is poured into container

A

the final temperature is

T_{2}

(heat loss is negligible)

Q. A beaker contains

200 g

of water. The heat capacity of the beaker is equal to that of

20 g

of water. The initial temperature of water in the beaker is

20^{\circ} C

. If

440 g

of hot water at

92^{\circ} C

is poured in it, the final temperature (neglecting radiation loss) will be nearest to

Q. A vessel contains

110 g

of water. The heat capacity of the vessel is equal to that of

10 g

of water. The initial temperature of water in the vessel is

10^{\circ} C

. While the water and vessel are in thermal equilibrium,

220 g

of hot water at

70^{\circ} C

is poured into the vessel. Find the final temperature of the vessel + water system (neglecting radiation loss).

Join BYJU'S Learning Program

A bucket contains 8 kg of water at 25∘C and 2 kg of water at 80∘C is poured into it. Neglecting the heat absorbed by the bucket, calculate the final temperature of water.

The correct option is A 36∘CLet s be the specific heat capacity of water and the final temperature be T. Heat lost by hot water = Heat gained by cold water ⇒2×s×(80∘C−T)=8×s×(T−25∘C) ⇒160∘C−2T=8T−200∘C ⇒T=36∘C

A bucket contains $8 kg$ of water at $25^{\circ} C$ and $2 kg$ of water at $80^{\circ} C$ is poured into it. Neglecting the heat absorbed by the bucket, calculate the final temperature of water.