Question

A bucket has 7/2 litres of water in it. A leakingtap fills 1/4 litre of water in one hour. If the bucket is kept below the leaking tap, how much water will be there in it after 1-1/2 hours ?

Answer 1

$$\begin{gathered} \mathrm{Water}\mathrm{in}\mathrm{the}\mathrm{bucket}=\frac{7}{2}\mathrm{l} \\ \mathrm{Water}\mathrm{filled}\mathrm{by}\mathrm{the}\mathrm{leaking}\mathrm{tap}\mathrm{in}\mathrm{an}\mathrm{hour}=\frac{1}{4}\mathrm{l} \\ \mathrm{Water}\mathrm{filled}\mathrm{by}\mathrm{the}\mathrm{leaking}\mathrm{tap}\mathrm{in}\mathrm{half}\mathrm{an}\mathrm{hour}=\frac{1}{8}\mathrm{l} \\ \mathrm{Water}\mathrm{in}\mathrm{the}\mathrm{bucket}\mathrm{after}1\frac{1}{2}\mathrm{hr}=\frac{7}{2}\mathrm{l}+\frac{1}{4}\mathrm{l}+\frac{1}{8}\mathrm{l}=\frac{31}{8}\mathrm{l}=3.875\mathrm{l} \end{gathered}$$