Question

A bucket, in the shape of a frustum of a cone, has a height of $6cm$. Its top and its bottom have radii of $24cm$ and $16cm$ respectively. Find its curved surface area.

Answer 1

The bucket is in the shape of a frustum.

The slant height of frustum

$=\sqrt{\left(\right(Topradius-Bottomradius{)}^2+(Height{)}^2}$

Therefore, slant height of the bucket

$l=\sqrt{(24-16{)}^2+6^2}=10$ $m$

Therefore, its curved surface area = $\pi l(R+r)=\pi \left(10\right)(24+16)=400\pi$ $m^2$