A bucket is in the shape of the frustum of a right circular cone, whose radii are $6$ mm and $24$ mm. The curved surface area is $450$ mm. Find the slant height. (Use $π = 3$ ).

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Solution

The correct option is A $5$ mm
Curved surface area $= π (R + r) s$
$450 = 3 \times (24 + 6) \times s$
$\frac{450}{90} = s$

$s = 5$ mm

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A bucket is in the shape of the frustum of a right circular cone, whose radii are 6mm and 24 mm. The curved surface area is 450mm. Find the slant height. (Use π=3).

The correct option is A 5 mmCurved surface area =π(R+r)s 450=3×(24+6)×s45090=ss=5 mm

A bucket is in the shape of the frustum of a right circular cone, whose radii are $6$ mm and $24$ mm. The curved surface area is $450$ mm. Find the slant height. (Use $π = 3$ ).

The correct option is A $5$ mm
Curved surface area $= π (R + r) s$
$450 = 3 \times (24 + 6) \times s$
$\frac{450}{90} = s$

$s = 5$ mm