A bucket open at the top, and made up of a metal sheet is in the form of a frustum of a cone. The depth of the bucket is 24 cm and the diameters of its upper and lower circular ends are 30 cm and 10 cm respectively. Find the cost of metal sheet used in it at the rate of Rs.10 per 100 $c m^{2}$ . (Use $π$ = 3.14).

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Solution

Height of frustum = 24cm , $r_{1} = 15 c m$
$r_{2} = 5 c m$

$L = \sqrt{(r_{1} - r_{2})^{2} + h^{2}} = 26 c m$

l = 26 cm

To find the cost of the metal sheet we have to take the CSA of the bucket. $(r_{1} + r_{2}) l$

so the ans will be 1632.8 cm

The cost of the metal sheet will be Rs 10 $\times$ 1632.8 = Rs 16328

The cost of metal sheet used is Rs 16328.

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