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Byju's Answer
Standard XII
Chemistry
Basic Buffer Action
A buffer of ...
Question
A buffer of
p
H
=
9.26
is made by dissolving
x
moles of ammonium sulphate and 0.1 mole of ammonia into 100 mL solution. If
p
K
b
of ammonia is 4.74, calculate value of
x
.
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Solution
p
H
=
p
K
b
+
log
[
s
a
l
t
]
[
b
a
s
e
]
Given,
p
H
=
9.26
,
p
K
b
=
4.76
[
s
a
l
t
]
=
x
m
o
l
e
/
L
[
b
a
s
e
]
=
(
0.1
×
1000
)
/
100
=
1
M
o
l
/
L
Now,
9.26
=
4.74
+
log
x
1
⇒
4.52
=
log
x
⇒
x
=
10
−
4.52
=
3.02
×
10
−
5
.
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0
Similar questions
Q.
A buffer of
p
H
9.26
is made by dissolving
x
moles of ammonium sulphate and
0.1
mole of ammonia into
100
m
L
solution. If
p
K
b
of ammonia is
4.74
, calculate value of
x
.
Q.
40 ml of 0.1 M ammonia solution is mixed with 20 ml of 0.1 M HCl. What is the pH of the mixture? (
p
K
b
of
ammonia solution is 4.74)
Q.
A buffer solution is made by dissolving by
10
−
2
mole
C
H
3
C
O
O
H
and
10
−
2
mole of
C
H
3
C
O
O
⊖
N
a
⊕
in 100 ml of water.
(i) What is the pH of solution ?
(ii) If this solution is poured into a container having 10,000 litre of
H
2
O
, then what is the new pH?
Q.
One litre of a buffer solution is prepared by dissolving
0.6
mole of
N
H
3
and
0.4
mole of
N
H
4
C
l
. What is the pH of the solution? for
N
H
3
,
K
b
=
1.85
×
10
−
5
.
(i) What is the pH of the buffer after addition of
0.1
mole of
H
C
l
.
(ii) What is the pH of the buffer after addition of
0.1
mole of
N
a
O
H
Q.
Calculate the pH of the buffer solution prepared by mixing, 50 ml of 0.1 M
N
H
4
O
H
and 25 ml of 2 M
N
H
4
C
I
(
p
K
b
of
N
H
4
O
H
is 4.8).
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