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Question

A buffer solution is made by dissolving by 102 mole CH3COOH and 102 mole of CH3COONa in 100 ml of water.
(i) What is the pH of solution ?
(ii) If this solution is poured into a container having 10,000 litre of H2O, then what is the new pH?

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Solution

(i) [CH3COOH]=102100×103=1020.1,[CH3COONa]=1020.1
pH=pKa+log[CH3COONa][CH3COOH]=pKa+log102/0.1102/0.1
pH=pKa
(ii) Total volume= V=10000+0.1=10000.1
[CH3COOH]=102V,[CH3COONa]=102V
pH=pKa+log102/V102/V=pKa .

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