A buffer solution is prepared by mixing 10 ml of 1.0 M acetic acid and 20 ml of 0.5 M sodium acetate and then diluted to 100 ml with distilled water. If the pKa of CH3COOH is 4.76, what is the pH of the buffer solution prepared?
A
5.21
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B
4.76
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C
4.34
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D
5.21
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Solution
The correct option is B 4.76 mole of sodium acetate=20×0.5=10 mole of acetic acid=10×1=10 total volume after dilution = 100+20+10=130 ml [sodium acetate]=10130 [acetic acid]=10130 using Henderson Equation. pH=pKa+log[salt][acid] pH=4.76+log⎛⎜
⎜
⎜⎝1013010130⎞⎟
⎟
⎟⎠ pH=4.76+log(1010) pH=4.76