CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A buffer solution of pH=4 is to be prepared, using CH3COOH and CH3COONa. The concentration of acetic acid and sodium acetate are 110 M and x M. How much will the pH be if 1.5 L of H2O is added to above buffer ? Ka(CH3COOH)=4.7447

A
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 4
Using the Henderson-Hasselbalch equation for weak acid:
pH=pKa+log[CH3COONa][CH3COOH]
pH=log Ka+log[CH3COONa][CH3COOH]
4=log 1.8×105+logx110
4=4.7447+log 10x
x=0.018 M
If 1.5L of H2O is added it increases the volume, thereby decreasing concentration of both acid and salt. The ratio log[Salt][Acid] remains constant.
So pH remains same that is pH=4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon